-4.9x^2+10x+828=0

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Solution for -4.9x^2+10x+828=0 equation:



-4.9x^2+10x+828=0
a = -4.9; b = 10; c = +828;
Δ = b2-4ac
Δ = 102-4·(-4.9)·828
Δ = 16328.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-\sqrt{16328.8}}{2*-4.9}=\frac{-10-\sqrt{16328.8}}{-9.8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+\sqrt{16328.8}}{2*-4.9}=\frac{-10+\sqrt{16328.8}}{-9.8} $

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